2015-10-13 0:28 GMT-06:00 Pallavi Banerjee
<[email protected]>:
> Shouldn't we go from the more rigid potentials to the softer ones? This is
> why I choose to do IBI on bonded followed by non-bonded. And also from the
> hexane tutorial, it looks like the same has been done. Am I missing
> something here?
You are right, but because bonded interactions are so rigid, simple
Boltzmann inversion is usually enough.
And you could derive these interaction from a single chain in vacuum.
And iterative Boltzmann inversion is only needed for non-bonded
interactions.


>
> Thanks for your patience!
>
> -Pallavi Banerjee
>
> On Monday, October 12, 2015 at 7:27:00 PM UTC+5:30, Pallavi Banerjee wrote:
>>
>> Hello all,
>>
>> I have been wondering whether we really need to do the processing of
>> bonded potentials to provide as input for ibi-bonded. The tutorial for
>> hexane (ibi-bonded) shows that the processing is done in the step_000. Am I
>> carrying out a useless repeat of potential processing if I do one before
>> this step?
>>
>> Thanks!
>>
>> -Pallavi Banerjee
>
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