Hi All,
perl has a nice way of padding variables to line
up columns:
print "\t$a", ' 'x($block - length($a)), "\tb:
$b \n";
Is there something similar in bash? This hurts
my eyes:
# -----------------------------------
space_over() # echo $1 spaces
{
i=$1
while (( $i > 0 )); do
echo -n " "
i=$(($i-1))
done
}
wide=10
vars='abcd bcdef cdefgh defghij'
for v in $vars; do
echo -en "\tThe length of ($v)"
space_over "$(($wide-${#v}))"
echo "is ${#v} and $wide minus ${#v} is
$(($wide-${#v}))"
done
# -----------------------------------
I guess I don't need to mention I'm just learning
bash.
Jim
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