Thanks, I guess I'll do it with a variable like you suggested Jay
> I'm also not sure if I understand what you want, but here's my best > guess. > > When invoked "inline" (with a . at the beginning of a line), I don't > think you can get at the path name, but here are a couple of > alternatives > > ## .bashrc > export MYAPPHOME=/opt/myapp > . $MYAPPHOME/bin/config > > ## /opt/myapp/bin/config > echo $MYAPPHOME > pushd $MYAPPHOME > # whatever > popd > > > or alternatively: > > ## .bashrc > export MYAPPCONFIG=/opt/myapp/bin/config > export MYAPPHOME=`/usr/bin/dirname $MYAPCONFIG`/.. > . $MYAPPCONFIG > > ## /opt/myapp/bin/config is the same... > > > > On Monday, Sep 29, 2003, at 05:18 US/Pacific, Jay Strauss wrote: > > > Hi, > > > > I want to get the path of the file from a script called from .bashrc. > > Like: > > > > ##.bashrc > > . /opt/myapp/bin/config > > > > > > ## /opt/myapp/bin/config > > pwd > > echo $0 > > > > > > In this case during login: > > pwd = /home/jstrauss > > $0 = -bash > > > > I'd like to get a variable with the value /opt/myapp/bin/config > > but I can't find a combination of commands that will give my that > > during > > login or su > > > > Jay > > > > > > _______________________________________________ > > vox-tech mailing list > > [EMAIL PROTECTED] > > http://lists.lugod.org/mailman/listinfo/vox-tech > > > > _______________________________________________ > vox-tech mailing list > [EMAIL PROTECTED] > http://lists.lugod.org/mailman/listinfo/vox-tech > > _______________________________________________ vox-tech mailing list [EMAIL PROTECTED] http://lists.lugod.org/mailman/listinfo/vox-tech
