lfd_lzo.c defines size of the output buffer as: static int zbuf_size = VTUN_FRAME_SIZE * VTUN_FRAME_SIZE / 64 + 16 + 3;
This translates to 65555 bytes Where does this value come from? According to LZO FAQ http://www.oberhumer.com/opensource/lzo/lzofaq.php LZO will expand incompressible data by a little amount. I still haven't computed the exact values, but I suggest using these formulas for a worst-case expansion calculation: Algorithm LZO1, LZO1A, LZO1B, LZO1C, LZO1F, LZO1X, LZO1Y, LZO1Z: ---------------------------------------------------------------- output_block_size = input_block_size + (input_block_size / 16) + 64 + 3 Which comes to 2245 bytes
vtun_lzo.patch
Description: Binary data
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