I'm using IE. I tried using gsub!(/Â/, ""), but I couldn't remove the
remaining spaces. It took a long time, but I think I figured it out
using this:
x = "3       Jubitz Travel Center              Â
Portland,OR"
b = x.gsub(x[/(\d+)(\b[^0-9A-Za-z]{1,}\b)/], '') # gets rid of the
beginning number/funky chars
puts b.gsub(b[/(\b[^0-9A-Za-z]{1,}\b)(\w+)(,..)\Z/], '') # gets rid of
the second set of funky chars and city/state
On Mar 9, 3:36 pm, Ethan <[email protected]> wrote:
> Is this in IE or firefox?
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