Maybe "wavesandbox.com" is an alias for "wave.wavesandbox.com"?
Anyhow, wave.* is not defined anywhere in the spec. So no, you do have to use @wave.xmppnews.com, otherwise it will go to your normal xmpp account. On Mon, Nov 2, 2009 at 12:54 PM, bear <[email protected]> wrote: > > Have to admit this is some cool stuff ;) > > I have my wave server setup as a component wave.xmppnews.com to my > xmppnews.com server - my JID is [email protected]. > > In order for my dev sandbox account to send to the federated server I > had to use [email protected] as the contact id instead of the JID > - is this expected? I'm asking because my sandbox account is > [email protected] but I see in the data that the wave server > identifies itself as @wave.wavesandbox.com > > Also, I can type in the sandbox client and see the updates on the > command line client window, but nothing I type in the command line > client gets sent to the sandbox account. > > More details later as I figure out how to decode the log streams and > see if there are any error messages :) > > but I did get data flowing sandbox -> federated so that's a partial > win :) > > thanks, > > > > -- ~devyn --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Wave Protocol" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/wave-protocol?hl=en -~----------~----~----~----~------~----~------~--~---
