Howard,
I am indebted to you. In fact your description fits the code as is, but
that led me to look closer and I found a full stop causing a full stop
-) - which led to the remaining error - a letter missing from a file
name!!
Joseph
> This warning means you have an error in your result set, which is
> usually caused by an error in your SQL statement.
>
> From the names of your variables, it looks like you are trying to get
> an array out of your SQL statement and not the result set.
>
> You should be doing something like this:
>
> $result = mysql_query($sql, $db);
> if (!$result) echo mysql_error();
> else
> {
> while ($row = mysql_fetch_array($result))
> {
> // stuff
> }
> }
>
> Smile-Poet wrote:
>
> > I have this line
> >
> > while($row = mysql_fetch_array($sql)){
> >
> > which gets the error
> >
> > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result
> > resource
>
> --
> ::::::::::::::::::::::::::::::
> Howard Cheng
> http://www.howcheng.com/
> Wise-cracking quote goes here.
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