if ($numrows = 0) {
should be
if ($numrows == 0) {
comparison, rather than assignment.
- Stephen
On 8/5/05, Galatek Webmaster <[EMAIL PROTECTED]> wrote:
> Hello all ( at least I hope it is getting somewhere, my last few emails
> disappeared)
> Got an irritating little problem that is starting to drive me up the
> wall, I am making an online catalogue for a client
> using PHP and MySQL to populate the pages. I want the code to check to
> see if any rows were returned by the query
> and, if not, display a message saying that the category is emtp.. easy
> right? just simple case of using mysql_num_rows() on the
> query result string and whalah.. but it is being stubborn.
> mysql_num_rows is returning a blank string instead of 0 or the number
> of rows actually there. Heres a snippet of the code
>
> <snippet begins>
> $sql = sprintf("SELECT * FROM CatalogueItems WHERE
> fldcategory=`%s`",$category);
> $result = mysql_query($sql);
> if (!$result) { die("Database Connection Error, Contact the site
> administrator"); }
> $numrows = mysql_num_rows($result);
> if ($numrows = 0) {
> echo '<center><font color="red" style="font-weight: bolder">No items
> exist for this category</font><br>
> <br><a href="./index.php" class="itemlist">Back to home
> page</a></center>';
> } else {
> .// fetch results arrays and create dynamic page
> .
> .
> .
> }
>
> </snippet>
>
> One category is empty and another has 6 rows, but when doing this code
> on either of the categories, mysq_num_rows returns " " instead of an int
> value, so nothign whatsoever is displayed. if I use ($numrows == 0) then
> it displays the warning text saying nothing is in the category, if I use
> ($numrows < 1) it displays nothing whatsoever. I have tried debugging by
> putting dynamic comments in the code, but the value output by
> mysql_num_rows is always a blank space.
>
> Any help on this before i go completely nuts is appreciated much in advance.
>
> Charles R King
> Galatek Webmaster
>
>
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