Experimenting some and it seems it might be as simple as: WSGIScriptAlias /appName /opt/web2py-1.49/wsgihandler.py/appName
Of course this would require multiple handlers for each application. Is there a better way? On Nov 11, 4:10 pm, Mark Larsen <[EMAIL PROTECTED]> wrote: > web2py users, > > I'm running apache2 with mod_wsgi. I ScriptAlias the wsgihandler.py > not as the root of the server but with it's own directory. From my > vhost file: > > WSGIScriptAlias /appName /opt/web2py-1.49/wsgihandler.py > <Directory "/opt/web2py-1.49"> > Order allow,deny > Allow from all > </Directory> > > To access the application, I need to dohttp://servername.com/appName/appName. > What's the best way to route off that second appName. I tried > "renaming" my application as init in the applications folder but > web2py then cuts off the first appName and apache fails to use the > wsgi server. > > Thanks, > > Mark --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
