e.g.:
In [80]: L
Out[80]: ['db', '_5', '_31', '5']
In [81]: L.append('_a')
In [82]: L.sort(reverse=True)
In [83]: L
Out[83]: ['db', '_a', '_5', '_31', '5']
---- so if 'db' weren't in the list, '_a' would be L[0], ahead of '_5' and
'_31' ... and other internal references like that.
On Wed, Dec 17, 2008 at 5:15 PM, Yarko Tymciurak <[email protected]> wrote:
> ... this seems like it works even if the initial object isn't named
> '_something'.... as long as its not '_3' (or some other number) this still
> looks good... will get you a name before an internal reference.
>
>
> On Wed, Dec 17, 2008 at 5:06 PM, Yarko Tymciurak <[email protected]>wrote:
>
>> Maybe something on the order of this might reliably get you what you want
>> (I don't check for no objects case - you can add that):
>>
>> def ngetName(obj):
>> ....: n=[k for k,v in globals().items() if v is obj]
>> ....: n.sort(reverse=True)
>> ....: return n[0]
>>
>>
>>
>>
>> On Wed, Dec 17, 2008 at 5:00 PM, Yarko Tymciurak <[email protected]>wrote:
>>
>>> I'd left my last python instance up; here's your "copy" version (which
>>> just copies the current references; it _does_ seem to get rid of the
>>> transient, underscore-only (one, two, three) references ... but that seems
>>> little.
>>>
>>> Instead of copy, you could do k.sort(reverse=True), and then return k[0]
>>> - that would at least be more reliable.
>>>
>>> Here's my results with your latest suggestion:
>>>
>>> In [50]: import copy
>>>
>>> In [51]: def cgetName(obj):
>>> ....: g=copy.copy(globals())
>>> ....: return([k for k,v in g.items() if v is obj]) # don't need
>>> 'None' to return list; empty list o.k.
>>> ....:
>>>
>>> In [52]: cgetName(f._db)
>>> Out[52]: ['db', '_5', '_31']
>>>
>>> In [53]: cgetName(db)
>>> Out[53]: ['db', '_5', '_31']
>>>
>>> In [54]: getName(f._db)
>>> Out[54]: ['db', '_5', '_31']
>>>
>>> In [55]: getName(db)
>>> Out[55]: ['db', '_5', '_31']
>>>
>>> --------
>>> Regards,
>>> Yarko
>>>
>>>
>>> On Wed, Dec 17, 2008 at 4:52 PM, Yarko Tymciurak <[email protected]>wrote:
>>>
>>>> depending on what you've done / referenced before you get the copy, your
>>>> list will differ...
>>>>
>>>> The underscores (single, double, triple) do appear to be transient; the
>>>> others are internal references.
>>>>
>>>> No matter what, that ****[0] just won't work. I've already tried this
>>>> on a couple of different machines, and I _can_ get to where 'foobar' is
>>>> item[0] in the list - sometimes, and not reliably. More often, it's
>>>> _sometimes_ item[0]; an activity (like a reference) disrupts that list.
>>>>
>>>> Anyway, this is interesting - good luck. I think you'll have to get the
>>>> list, and manually remove the '_names' (including '__);
>>>>
>>>> Look at my first "test results" post of this thread - '_5' was at the
>>>> head of that list (due to what activity happened, and how references were
>>>> generated) ---- it stayed at the head of the list; '_5' does not seem
>>>> like
>>>> intermediate results, rather internally generated reference(s). Those
>>>> references seem to "stay around" ... don't know for what length of time,
>>>> but
>>>> certainly the duration of my tests (gc might clean them up).
>>>>
>>>> Another time, '__' was at the head, but (as you noticed) that's
>>>> transient, and went away.
>>>>
>>>> I think you have _incidentally_ hit on cases where item[0] just happens
>>>> to be what you want. It doesn't look to me like you can count on that.
>>>>
>>>> Regards,
>>>> Yarko
>>>>
>>>>
>>>> On Wed, Dec 17, 2008 at 4:30 PM, DenesL <[email protected]> wrote:
>>>>
>>>>>
>>>>> Yarko,
>>>>>
>>>>> I think those underscored keys come from intermediate results.
>>>>> Not sure about those double and triple ones.
>>>>> An improved version (of either J's or M's) would have to work with a
>>>>> copy of globals:
>>>>>
>>>>> import copy
>>>>> def getName(obj):
>>>>> g=copy.copy(globals())
>>>>> return([k for k,v in g.items() if v is obj]+[None])[0]
>>>>>
>>>>> I don't get any underscores this way, how about you?.
>>>>>
>>>>> >>>>>
>>>>>
>>>>
>>>
>>
>
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