On Jan 11, 11:28 am, Fran <[email protected]> wrote:
> Strangely enough I also see the identical UUIDs for the 2 default
> records I create during my app intialisation with consecutive:
> db['%s' % table].insert(...)
> (I'm aware the time must be almost identical & this is one of the
> inputs for uuid, but we shouldn't be able to create identical
> records...)
I fixed this part by changing to:
SQLField('uuid',length=64)
& doing the uuid.uuid4() within each record insertion instead of as
the default.
F
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