Thank you massimo for your prompt response.

I didn't very well explained my problem.

I have 3 tables: category, subcategory, subsubcategory

subcategory references category
subsubcategory references  subcategory

Have you en example for this.

Thank you


On Jan 11, 3:02 pm, mdipierro <[email protected]> wrote:
> Here are two examples:
> 1)
>
> db.define_table('a',db.Field('name'))
> db.define_table('b',db.Field('name'))
> db.define_table('t',db.Field('name'),db.Field('aid',db.a),db.Field
> ('bid',db.b))
> rows=db().select(db.t.name,db.a.name,db.b.name,left=[db.a.on
> (db.a.id==db.t.aid),db.b.on(db.b.id==db.t.bid)])
>
> 2)
> db.define_table('a',db.Field('name'))
> db.define_table('t',db.Field('name'),db.Field('aid',db.a),db.Field
> ('bid',db.a))
> rows=db().select(db.t.name,db.a.name,db.a.with_alias('b').name,left=
> [db.a.on(db.a.id==db.t.aid),db.a.with_alias('b').on
> (db.a.id==db.t.bid)])
>
> On Jan 11, 1:24 pm, ionel <[email protected]> wrote:
>
> > Hello,
>
> > Do anybody knows how to implement LEFT OUTER JOIN with 3 tables in
> > web2py?
>
> > I saw the example with 2 tables in massimo's book, but I can't figure
> > out how to implement it with 3 tables.
>
> > Thank you
>
> > ionel
>
>
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