You cannnot with SQLFORM, You can with FORM or with form_factory.
On Feb 28, 9:58 pm, weheh <[email protected]> wrote: > I have 2 tables that are linked: > > db.define_table('x',SQLField('name','string')) > > db.define_table('y',SQLField('x',db.x),SQLField('name','string')) > > I want my create() controller to display both tables, x and y, on the > same form and makes sure that y correctly links to x. > > Can SQLFORM implement this or do I need to use the FORM construct (or > something else)? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
