you are calling db.table1 somewhere. In my code there is no db.table1 at
all....just tried, works. Readable example
tablename = 'test1'
labels = dict(test1_foo='test1label')
db.define_table(tablename,
Field('foo', label=labels["%s_foo" % tablename])
)
BTW: you'd be better off separating table name and field name in your
labels dict (or even, structure it as
dict(table=tablename,fields=dict(fieldname=label))).
If you have a table named *foo* with a field *bar* and a table *foob* with
a column *ar* you are going to display the same label for both ;-)
On Thursday, October 18, 2012 11:09:56 PM UTC+2, Richard wrote:
>
> I still get <type 'exceptions.AttributeError'> 'DAL' object has no
> attribute 'table1'
>
> You right that I didn't need call db.table._tablename and
> db.table.field.name... I was just trying something else before then I
> forget I didn't need to call those attributes.
>
> Anyway, I think it is not possible since model is not yet define.
>
> FYI dblables_en is a dict like this one {'table1field1':
> 'field1LableStoreInDb'}
>
> Thanks.
>
> Richard
>
> On Thu, Oct 18, 2012 at 4:40 PM, Niphlod <nip...@gmail.com
> <javascript:>>wrote:
>
>> you are asking to python to evaluate a variable that doesn't exists.
>> It seems that you know the tablename and fields in advance (because
>> dblabels_en is somewhat filled already) so why can't you just
>>
>> tablename = 'test1'
>> db.define_table(tablename,
>> Field('foo', label=T(dblabels_en["%s_foo" % tablename])))
>>
>> ?
>>
>>
>> On Thursday, October 18, 2012 9:57:09 PM UTC+2, Richard wrote:
>>>
>>> Hello,
>>>
>>> Is it possible to do that?
>>> db.define_table(...
>>> Field(...
>>> label=T(dblabels_en[db.table._**tablename+db.table.field.name]**)
>>>
>>> I can do
>>> db.define_table(...)
>>> db.table.field.lable=T(**dblabels_en[db.table._**tablename+
>>> db.table.field.name]**)
>>>
>>> Inside table model definition "table" is not yet define then I can refer
>>> to it.
>>>
>>> I try with lambda with no succes.
>>>
>>> Do you see a way to refer to the db.table._tablename in order to make it
>>> execute only once that the model is defined?
>>>
>>> Thanks
>>>
>>> Richard
>>>
>> --
>>
>>
>>
>>
>
>
--
