solved > > when use in controller default.py > def sql_form(): > sqlform=SQLFORM.grid(db.mydb, fields=[db.mydbname.name, > db.mydbname.info]) > return dict(sqlform=sqlform) > > >
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solved > > when use in controller default.py > def sql_form(): > sqlform=SQLFORM.grid(db.mydb, fields=[db.mydbname.name, > db.mydbname.info]) > return dict(sqlform=sqlform) > > >
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