Hi again.
First of all: thanks a lot for your answer Massimo, I know you have a lot
to do, thanks for patiently helping the rookies.
I had already tried that code (saw from an old post) but it dont work too.
Tried again and it gives the same exact error. This is the full code I used:
import os
import shutil
form = FORM(INPUT(_type='file',_name='myfile'),INPUT(_type='submit'))
if form.accepts(request.vars,session):
shutil.copyfileobj(form.vars.myfile.file, open(os.path.join(request.
folder,'uploads','filename.wav'),'wb'))
response.flash = 'form accepted'
elif form.errors:
response.flash = 'Error'
return dict(form=form)
I tried also with SQLFORM.factory but it is the same.
Small files work, larger files (200 mbs) give this error.
Some tips?
Sábado, 1 de Dezembro de 2012 18:55:01 UTC, Massimo Di Pierro escreveu:
>
> You cannot do:
>
> open(...,'wb').write(form.vars.myfile.file.read())
>
> because this read the entire file in memory before writing it. You need to
> use
> http://docs.python.org/2/library/shutil.html
> and do
>
> shutil.copyfileobj(form.vars.myfile.file, open(...,'wb'))
>
> Massimo
>
>
> On Friday, 30 November 2012 10:11:48 UTC-6, Paulo wrote:
>>
>> Hi!
>>
>> I'm trying to create a very simple upload field, without any complex
>> mechanism. A user just uploads a file to a folder in the server (apache),
>> without web2py changing the file name, and without any db. I have some
>> dozens of files already in a folder in the server, I just need an upload
>> form to send new files easly, without having to go personally with an Usb
>> Pen to the server to copy new files.
>>
>> But I'm having an hard time doing it, and dont know why. With small files
>> (2mb docx file) it works perfectly. But when uploading a 300mbs wav file it
>> gives an error ticket:
>> <type 'exceptions.MemoryError'>
>> TRACEBACK
>>
>> 1.
>> 2.
>> 3.
>> 4.
>> 5.
>> 6.
>> 7.
>> 8.
>> 9.
>> 10.
>> 11.
>> 12.
>> 13.
>> 14.
>> 15.
>> 16.
>> 17.
>> 18.
>> 19.
>> 20.
>> 21.
>> 22.
>> 23.
>> 24.
>> 25.
>> 26.
>> 27.
>> 28.
>> 29.
>> 30.
>> 31.
>> 32.
>>
>> Traceback (most recent call last):
>> File "D:\web2py\gluon\restricted.py", line 212, in restricted
>> exec ccode in environment
>> File
>> "D:/web2py/applications/Upload_Fala_Bracarense/controllers/default.py"
>> <https://cehum.ilch.uminho.pt/admin/default/edit/Upload_Fala_Bracarense/controllers/default.py>,
>> line 121, in <module>
>> File "D:\web2py\gluon\globals.py", line 188, in <lambda>
>> self._caller = lambda f: f()
>> File
>> "D:/web2py/applications/Upload_Fala_Bracarense/controllers/default.py"
>> <https://cehum.ilch.uminho.pt/admin/default/edit/Upload_Fala_Bracarense/controllers/default.py>,
>> line 28, in index
>> form = SQLFORM.factory(Field('myfile', 'upload',
>> uploadfolder='/static')).process()
>> File "D:\web2py\gluon\html.py", line 2170, in process
>> self.validate(**kwargs)
>> File "D:\web2py\gluon\html.py", line 2109, in validate
>> if self.accepts(**kwargs):
>> File "D:\web2py\gluon\sqlhtml.py", line 1281, in accepts
>> **kwargs
>> File "D:\web2py\gluon\html.py", line 2022, in accepts
>> self._traverse(False, hideerror)
>> File "D:\web2py\gluon\html.py", line 842, in _traverse
>> newstatus = c._traverse(status, hideerror) and newstatus
>> File "D:\web2py\gluon\html.py", line 842, in _traverse
>> newstatus = c._traverse(status, hideerror) and newstatus
>> File "D:\web2py\gluon\html.py", line 842, in _traverse
>> newstatus = c._traverse(status, hideerror) and newstatus
>> File "D:\web2py\gluon\html.py", line 842, in _traverse
>> newstatus = c._traverse(status, hideerror) and newstatus
>> File "D:\web2py\gluon\html.py", line 853, in _traverse
>> self._postprocessing()
>> File "D:\web2py\gluon\html.py", line 1762, in _postprocessing
>> _value = str(self['_value'])
>> File "C:\Python27\Lib\cgi.py", line 515, in __repr__
>> self.name, self.filename, self.value)
>> MemoryError
>>
>> IN FILE:
>> D:\WEB2PY\APPLICATIONS\UPLOAD_FALA_BRACARENSE\CONTROLLERS/DEFAULT.PY
>> I have tried a lot of diferent ways. I have read everything I could find
>> in the web. I found a topic with the same problem but no solution I could
>> use. Anyone can help with some tips?
>>
>> This the code in the controller:
>>
>> import os
>>
>> def index():
>> form = FORM(INPUT(_type='file',_name='myfile'),INPUT(_type='submit'))
>> if form.accepts(request.vars,session):
>>
>> open(os.path.join(request.folder,'uploads','filename.wav'),'wb').write(form.vars.myfile.file.read())
>> return dict(form=form)
>>
>> I have tried a lot of different ways, this only an example. I used
>> SQLFORM.factory {form = SQLFORM.factory(Field('myfile', 'upload',
>> uploadfolder='/static')).process()}, shutil
>> {shutil.copyfileobj(request.vars.myfile.file,open(os.path.join(request.folder,'static','filename.txt'),'wb'))},
>>
>> and a lot of different code variants but none worked. Its allways the same:
>> with small files it works, with a 200mb file it gives an error.
>>
>>
>> Anyone can help me understand this problem? The max file size I need to
>> upload is 500mb. It will be used by only one person, with a login, so there
>> is no need to a complex mechanism, and files need to mantain the same name.
>> I just need the upload to work.
>>
>> Thanks and sorry for my bad english.
>>
>>
>>
>>
>> I want a user to be able to upload a file to a directory in the server
>> (apache), without changing the file name, and wihout databases. A simple
>> and direct upload, so a friend of mine can store some files in
>>
>
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