I have def download(): return response.download(request,db) in my
controller. But when I put {{=URL('default', 'download', args=row.image)}}
in my view I'm just getting a string. Perhaps because the file was not
saved to this directory?
On Wednesday, December 5, 2012 2:25:57 PM UTC, Anthony wrote:
>
> You do not specify the "uploads" directory in the URL. Instead, you need
> to define a function that calls response.download() and pass the filename
> to that function via the last URL argument (i.e., request.args[-1]). In
> fact, this function is already provided for you in the "welcome" app:
>
> def download():
> """
> allows downloading of uploaded files
> http://..../[app]/default/download/[filename]
> """
> return response.download(request,db)
>
> So, your URL should be URL('default', 'download', args=row.image).
>
> This is discussed
> here<http://web2py.com/books/default/chapter/29/03#An-image-blog>,
> here <http://web2py.com/books/default/chapter/29/07#SQLFORM-and-uploads>,
> here <http://web2py.com/books/default/chapter/29/04#response>, and
> here<http://www.web2py.com/examples/default/examples#database_examples>(example
> 33).
>
> Anthony
>
> On Wednesday, December 5, 2012 9:06:57 AM UTC-5, Daniele wrote:
>>
>> Guys I know this sounds simple but I'm having a hard time displaying
>> uploaded images. I have an upload field in my model where logged in users
>> can upload an image. But in my views when I try to do
>> {{=IMG(_src=URL('uploads/', row.image))}} where row is a variable that
>> refers to db(db.auth_user.id > 0).select() nothing is being returned.
>> However, row.image returns a string which is the name of the file.
>> How can I display the image correctly?
>>
>> Thanks!
>>
>
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