I've been studying the scheduler, but I think it fails in one of the things I need: "The web page must be updated as the process is being done" i.e. if the scheduler is doiing some background task, I need to update the web page with the progress of the task, but I don't find how to do it with the scheduler
2013/2/1 Massimo Di Pierro <[email protected]>: > yes. If the worker is not busy it starts the task immediately. You can also > have more than one worker. > > > On Friday, 1 February 2013 11:10:11 UTC-6, José Luis Redrejo Rodríguez > wrote: >> >> Thanks for your advice Massimo, but >> does the scheduler start inmediately when no worker has been used before? >> >> >> 2013/2/1 Massimo Di Pierro <[email protected]>: >> > All that you ask can be done using the scheduler except that your app >> > does >> > not start the process, but submits a request to the scheduler. The >> > scheduler >> > runs the app when a worker is available. This is to prevent spikes in >> > resource utilization when multiple processes start. The task can >> > communicate >> > with the app vid database and/or filesystem (which is ok but not 100% >> > satisfactory). Web2py can monitor and kill running scheduler tasks. >> > >> > This works well for most types of tasks but not for tasks that need a >> > lot of >> > IO with your application. I do not have a satisfactory solution in that >> > case. You want the tasks to have some way to communicate asynchronously >> > with >> > the client and this present major issues, some related with security. >> > >> > >> > On Friday, 1 February 2013 10:22:35 UTC-6, José Luis Redrejo Rodríguez >> > wrote: >> >> >> >> Hi, This is a question that has been asked several times in the list, >> >> and I have also had to implement this kind of app in the past. >> >> Now I'm also facing to another application where I need to run a >> >> resource_and_time_consuming process managed from web2py. >> >> >> >> The exact problem is: >> >> - From a web page, a long process must be started >> >> - The web page must be updated as the process is being done >> >> - The web page must be able to cancel the process. >> >> >> >> In the past I have had to deal with the fact of sessions lockings: >> >> web2py server doesn't react while the process is being executed. I've >> >> solved this by using session.forget(response), but this solution >> >> avoids the use of session variables to update the process in the >> >> original web page. >> >> >> >> I've used background processes, queues, etc, These solutions work when >> >> time is not an issue, but not when the synchronization between the >> >> process and the webpage must be fast and accurate >> >> >> >> I wonder if someone has a definitive pattern to do this kind of action. >> >> >> >> Regards >> >> José L. >> > >> > -- >> > >> > --- >> > You received this message because you are subscribed to the Google >> > Groups >> > "web2py-users" group. >> > To unsubscribe from this group and stop receiving emails from it, send >> > an >> > email to [email protected]. >> > For more options, visit https://groups.google.com/groups/opt_out. >> > >> > > > -- > > --- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/groups/opt_out. > > -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
