That's what we do, use the dirty cell function of JQGrid to get values,
smash them together in a string and pass back to a controller. Not very
elegant...
As someone else suggested, use the built in grid and avoid JQGrid if you
can.
On Tuesday, March 5, 2013 2:14:58 PM UTC-5, dlypka wrote:
>
> Perhaps get the id using that technique then use
> jquery('#myhiddenfieldid').val(id) store it in a hidden input field so the
> post back will then send it back to the web2py server code when you can
> easily access it. Or send it back right away using an ajax() call.
>
> On Tuesday, March 5, 2013 12:19:45 PM UTC-6, [email protected] wrote:
>>
>> Hi,
>>
>> I am newbee on Web2py, I am exploring it. I installed the jqGrid_plugin
>> that works fine. But now I should like to get back the id of the record or
>> the valor of a field but it is a JQuery that I don't know. I did this code:
>>
>> <h1>It is my table </h1>
>> <div class="tab" id="t" >
>> {{=plugin_jqgrid(db.image,columns=['id','titre'],height=300)}}
>> </div>
>>
>> <script>
>> jQuery('.tab').click(function(){jQuery('.tab').hide()})
>> </script>
>>
>> I have found the link to the jqGrid Demo but I don't understand how to
>> adapt this code I found, in web2py. There is maybe a special way :
>>
>> jQuery("#a1").click( function(){
>> var id = jQuery("#list5").jqGrid('getGridParam','selrow');
>> if (id) {
>> var ret = jQuery("#list5").jqGrid('getRowData',id);
>> alert("id="+ret.id+" invdate="+ret.invdate+"...");
>> } else { alert("Please select row");}
>>
>> Somebody can help me or give to me some links to read,
>>
>> Regards,
>> Bruno
>>
>>
>>
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