that works for a form but not for smartgrid. you can try this (a hack):
if request.vars.file != None:
db.client.filename.default = request.vars.file.filename
form = SQLFORM.smartgrid(db.client, fields=fields, linked_tables=['file'
])
On Friday, 22 March 2013 16:14:58 UTC-5, James Burke wrote:
>
> I'm having trouble working this one out. I've tried using the example in
> the book with no success.
>
> Model:
>
> db.define_table('file',
> Field('client', 'reference client'),
> Field('file', type='upload', autodelete=True),
> Field('filename', 'string'),
> format='%(file)s')
>
> Controller:
>
> def client():
> fields = dict(client=[db.client.company_name, db.client.live, db.client
> .contact_name, db.client.billing_code])
> form = SQLFORM.smartgrid(db.client, fields=fields, linked_tables=[
> 'file'])
>
> if request.vars.file != None:
> form.vars.filename = request.vars.file.filename
>
> return dict(form=form)
>
> Any help is appreciated.
>
> -James
>
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