Brian. I am confused. didn't you say the problem was with SQLite? What
does "swicthed to SQLite and it worked" means?

May I guess you are running Leopard? I know SQLite that ships with
Leopard has some issues.

If my assumption is correct, can you try the mac binary instead?

massimo

On May 2, 1:24 pm, Brian <[email protected]> wrote:
> I can switch to SQLite and it works perfect with or without the
> db.commit().
>
> On May 2, 1:06 pm, Brian <[email protected]> wrote:
>
> > Thanks for the response.
>
> > I added a commit() after my update_record but I'm still having the
> > same issue.
>
> > Using the DB admin, I edited a record on there and the same thing
> > happens: modify a record and it doesn't show up on a "db.part.id>0" in
> > the admin interface. I can view and modify it if I go to a specific
> > record, but can't view them all.
>
> > Is this something with postgres? Did I set something up wrong?
>
> > On May 2, 11:33 am, DenesL <[email protected]> wrote:
>
> > > Oops, more answers follow:
>
> > > On May 2, 8:23 am, Brian <[email protected]> wrote:
>
> > > > 2) What's the difference between an update and an update_record?
>
> > > update works on a set of records:
> > >    db(db.person.id>3).update(name='Ken')
>
> > > update_record is for a single record:
> > >     rows=db(db.person.id>2).select()
> > >     row=rows[0]
> > >     row.update_record(name='Curt')
>
> > > > 3) With the above example, is there anyway I can use a variable for a
> > > > field name? So instead of having a bunch of if's and elif's to go
> > > > through the field, I could do a:
> > > > db(row).update(updatedField = updatedData)
>
> > > The parameters are passed as a dictionary so you could create one.
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