You can use this:
Field('image_filename', readable=False, writable=False, compute = lambda
row: request.post_vars.image.filename),
On Monday, 25 March 2013 13:28:19 UTC-5, Tito Garrido wrote:
>
> Hi!
>
> Why this does not work:
> Field('image', 'upload', requires=IS_NOT_EMPTY(), uploadseparate=True,
> autodelete=True,),
> Field('image_filename', readable=False, writable=False, compute =
> lambda row: row.image.filename),
>
> Using a form I can follow the book and fill the image filename:
> if request.vars.image!=None:
> try:
> form.vars.image_filename = request.vars.image.filename
> except:
> form.vars.image_filename = request.vars.image
>
> How can I do the same using SQLFORM.grid?
>
> Regards,
>
> Tito
>
> --
>
> Linux User #387870
> .........____
> .... _/_õ|__|
> ..º[ .-.___.-._| . . . .
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