>
> for fieldname in db.mytab.fields:
db.mytab.fieldname.represent = lambda x,row:row[fieldname]
>
Two problems above. First, since "fieldname" is a variable, you cannot do
db.mytab.fieldname -- instead it should be db.mytab[fieldname]. Second, in
lambda x, row: row[fieldname]
the "fieldname" variable is defined in the scope outside the lambda
function. The last value held by "fieldname" will be the name of the last
field in the loop. The lambda functions won't actually be called until
after the loop has finished, so all of them will end up referring to the
fieldname of the last field. To get around this, you can pass in the
fieldname as a default argument to lambda:
lambda x, row, f=fieldname: row[f]
To make things even a bit simpler, you can take advantage of the fact that
you can iterate over the fields directly rather than their names (and you
can access each field's name via its "name" attribute):
for field in db.mytab:
field.represent = lambda x, row, f=field.name: row[f]
Anthony
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