Sorry Massimo, I left out part of the data model, which shows that 
auth_user can't be an element in the Party table.

Party can be either an organization or person, and organizations don't have 
auth_user fields. See data model examples: 

   - 
   
http://www.tsjensen.com/blog/post/2009/01/03/Party+Role+And+Party+Type+In+Data+Model.aspx
   - http://www.tdan.com/view-articles/5014/
   - http://www.essentialstrategies.com/publications/modeling/advanceddm.htm
   

Here's the real data model

db.define_table('Party', ## super-type for people and organizations
Field('partyTypeID','reference PartyType'), ## partyType is either person 
or organization
Field('displayName','string'))

db.define_table('Organization',
Field('partyID', 'reference Party'),
Field('organizationShortName','string'), 
Field('organizationFullName','string'))

auth.settings.extra_fields['auth_user']= [
    Field('partyID', 'reference Party'),
    Field('personMiddleName','string'),
    Field('gender','string'),    
  ]

So to get the names to display in a compute = lambda statement, a join 
would be required every time the table is listed.  I think that would be 
too big of a database hit. Instead, I can populate displayName but make 
sure that all update functions keep displayName accurate.

Thanks,

Alex


On Monday, May 6, 2013 5:52:48 AM UTC-7, Massimo Di Pierro wrote:
>
> You need to link Party to user not vice versa:
>
> auth.settings.extra_fields['auth_user']= [
> #    Field('partyID', 'reference Party'),
>     Field('personMiddleName','string'),
>     Field('gender','string'),    
>   ]
>
>
> db.define_table('Party', ## super-type for people and organizations
> Field('user_id','reference auth_user'),
> Field('partyTypeID','reference PartyType'), 
> Field('displayName','string'))
>
> db.Party.displayName.compute = lambda row: "%(first_name)s %(last_name)s" 
> % db.auth_user[row.user_id]
>
>
>
> On Monday, 6 May 2013 00:01:17 UTC-5, Alex Glaros wrote:
>>
>> In the controller below, how would I get auth_user.*first_name* and 
>> auth_user.*last_name* (concatenated) into table Party, field *displayName
>> *?
>>
>> In other words, I'd like field displayName to end up with first_name and 
>> last_name inside it.
>>
>> Party is the parent table and auth_user is the child table. Party is a 
>> super-type that can be either a person or an organization.  
>>
>> I think experienced programmers would recommend against hitting the 
>> database by joining Party table and auth_user table to create on-the-fly 
>> calculated field  for displayName whenever a list of Party names is 
>> displayed, right? I just have to be careful to update displayName whenever 
>> first_name and last_name are subject to change.
>>
>> *Controller*
>>
>> def add_new_people():   
>>     db.auth_user.partyID.readable = db.auth_user.partyID.writable = False ## 
>> don't let user see field thinking they have to fill it in
>>     db.Party.partyTypeID.readable = db.Party.partyTypeID.writable = False ## 
>> don't let user see field thinking they have to fill it in
>>     form=SQLFORM.factory(db.Party,db.auth_user)
>>     db.Party.partyTypeID.default = 1 ## sets up db so it's a person, not 
>> organization
>>     if form.process().accepted:
>>         partyID = db.Party.insert(**db.Party._filter_fields(form.vars))
>>         form.vars.partyID=partyID
>>         partyID = db.auth_user.insert(**db.auth_user._filter_fields(form.
>> vars))    
>>         response.flash='Thanks for filling the form'
>>     return dict(form=form)
>>
>>
>> *Model*
>>
>> auth.settings.extra_fields['auth_user']= [
>>     Field('partyID', 'reference Party'),
>>     Field('personMiddleName','string'),
>>     Field('gender','string'),    
>>   ]
>>
>>
>> db.define_table('Party', ## super-type for people and organizations
>> Field('partyTypeID','reference PartyType'), 
>> Field('displayName','string'))
>>
>>
>> thanks,
>>
>> Alex Glaros
>>
>

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