you mean that you want every possible url crawled and included in a sitemap ??? that's not web2py's specific, just take a crawler and generate the list of urls....
http://stackoverflow.com/questions/9561020/how-do-i-use-the-python-scrapy-module-to-list-all-the-urls-from-my-website On Wednesday, May 15, 2013 9:39:27 PM UTC+2, Omi Chiba wrote: > > I was thinking like this website where it will search for the directly > under the domain and generate sitemap.xml. > http://www.xml-sitemaps.com/ > > > > On Wednesday, May 15, 2013 1:59:26 PM UTC-5, Niphlod wrote: >> >> automatically from what list ? >> it's needed at least a list of urls to generate it .... >> >> On Wednesday, May 15, 2013 4:59:01 PM UTC+2, Omi Chiba wrote: >>> >>> Do we have the way to generate sitemap.xml automatically? >> >> -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
