You can use labda function in your db
Field('companyField name',db.linked table name, represent=lambda c,
row:field name of linked table(c),
requires=IS_IN_DB(db,'field.id','%(patient)s')),
On Wednesday, 26 June 2013 10:36:03 UTC+5:30, Tom Russell wrote:
>
> Another question on the smartgrid.
>
> I have linked tables in my smartgrid like:
>
> grid = SQLFORM.smartgrid(db.patient, deletable=True, editable=True,
> create=False, maxtextlength=64, paginate=25, links=links,
> links_in_grid=True, linked_tables=['emergencycontacts','dependents'])
>
> When clicking on the linked table it shows the id of patient since thats
> what reference but how can I show the name of the patient rather than the
> id of patient?
>
> Thanks,
>
> Tom
>
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