But in this case you don't have the id of the referenced record as relation key... I am not sure it's what you want. But you question is really vague so difficult to answer correctly to your I think :P
Richard On Thu, Jul 11, 2013 at 2:21 PM, Anthony <[email protected]> wrote: > On Thursday, July 11, 2013 1:21:11 PM UTC-4, greenpoise wrote: > >> I think I saw some light in here! this did the trick for me: >> >> Field('supplier', 'reference supplier',compute=lambda row: db.series(row. >> series).supplier**), >> > > Should be the same as: > > lambda row: row.series.supplier > > assuming row.series is a reference field referring to db.series. > > Anthony > > -- > > --- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/groups/opt_out. > > > -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
