This is easier than that.
First you create an action like this:
def serve_image():
id = request.args(0)
filename = get_image_filename_from(id)
stream = open(filename,'rb')
return response.stream(stream, attachment=True, filename=filename)
Then in your views you do:
<img src="{{=URL('serve_image',args='1234')}}" />
where 1234 is the id of the image you want.
On Tuesday, 16 July 2013 14:36:09 UTC-5, Diego Carvallo wrote:
>
> I am using Web2Py and need to serve images from folder external to Web2py,
> user images are dynamical and have to be loaded from a different system in
> the same server therefore they cannot be moved to be contained in the
> web2py application directory. So I cannot have a relative path to the
> images. Symbolink links are not an option.
>
> I was thinking the solution could be to serve JPG images from an action
> call or web service, this way the application can access the local file and
> return it programatically without having to move a single image. For
> example a view has the following code:
>
> <li class="file ext_jpg">
> <figure class="image_container">
> <img src=
> "controller_name/action_serving_images/unique_id_genereted_for_this_image.jpg"
>
> alt="">
> </figure>
> </li>
>
> having the Action:
> def action_serving_images(image_id)
> #obtain image based on it's unique generated id
> return image
>
> Or for the web service case:
> <li class="file ext_jpg">
> <figure class="image_container">
> <img src=
> "controller_name/service_serving_images/jpg/image/unique_id_genereted_for_this_image.jpg"
>
> alt="">
> </figure>
> </li>
>
> having the Service:
> def service_serving_images():
> return service()
>
> @service.jpg
> def image(image_id):
> #obtain image based on it's unique generated id
> return image
>
>
> 1. *Is any of these options possible?
> *
> 2. *How can I fetch the image and return it as a byte stream with
> the proper content-type so the browser can render it properly?
> *
> 3. *Do i need to create a special decorator for JPG in the case of the
> Service? How?*
>
>
> I posted the same question on
> stackoverflow<http://stackoverflow.com/questions/17667679/web2py-serve-images-from-action-call-or-web-service-call>
> but
> no answer yet... I appreciate any help!
>
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