You could first create the list of links in the controller and then pass it
to views via LOAD.
Take a look at this (didn't test it but the idea should be clear):
def getTags():
#get row object
tags = db().select(db.entry.tag,distinct=True)
#incialize taglist variable, start with <ul> tag
taglist = "<ul>"
#iterate over tags row and create the list of links
for t in tags:
taglist += "<li><a href='controller/function/" + t.id + "'>" +
t.name + "</a></li>"
#add closing </ul> tag at the end
taglist += "</ul>"
return XML(taglist)
On Friday, July 26, 2013 4:55:29 PM UTC+2, John Stricker wrote:
>
> I'm trying to display unique entry tags on all pages of a website in a bar
> on the left side. It seems the best place to put this info is in the
> 'default.html', which could call a function using LOAD.
>
> So in the controller i have:
>
> def getTags():
> """get a list of distinct entry tags"""
> return db().select(db.entry.tag,distinct=True)
>
> then in the default.html i have:
>
> {{tags = LOAD('default','getTags')}}
>
> it looks like the info is getting through, as when i can print out the
> list in default.html with {{=tags}} (which gives a bold header of
> 'entry.tag' followed by all unique values) but its unclear how to iterate
> over each of the values within the returned object. I'm guessing this is
> returning a row object? How do I iterate over it to create links for each
> unique entry?
>
>
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