ok that works but I have one other question, how would I use the belongs
operator If I want to refer a field by a name for example
instead of rows = db(db.zoo.tier.belongs([2, 3])).select() I want to do
this
rows = db(db.zoo.tier.belongs(["test 2", "test
3"])).select() ?
On Thursday, August 8, 2013 12:51:12 PM UTC-7, Massimo Di Pierro wrote:
>
> This
>
> rows = db(db.zoo.tier == 2).select()
>
> is equivalent to
>
> rows = db(db.zoo.tier.belongs([2])).select()
>
> you can do
>
> rows = db(db.zoo.tier.belongs([2, 3])).select()
>
>
> On Thursday, 8 August 2013 14:28:47 UTC-5, dave wrote:
>>
>> I have two tables defined as follows
>>
>> db.define_table('animals',
>> Field('type'),
>> format='%(type)s')
>>
>> db.define_table('zoo',
>> Field('name'),
>> Field('tier', 'reference animals'),
>> format='%(name)s'
>> )
>>
>> field type is a column with values like, test 1, test 2, test 3
>> now if I want to select all the records of table zoo with 'test 2' I can
>> do something like this
>>
>> rows = db(db.zoo.tier == "2").select()
>>
>> but why can't I do something like
>> db(db.zoo.tier.contains("2")).select() or
>> pass a list ["2", "3"] to the contains operator to get all the records
>> of "test 2" and "test 3"? can you suggest another way of implementing this?
>>
>
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