You can use a modified call() action:
def call_w_auth():
"""
exposes services. for example:
http://..../[app]/default/call/jsonrpc
decorate with @services.jsonrpc the functions to expose
supports xml, json, xmlrpc, jsonrpc, amfrpc, rss, csv
"""
auth.settings.allow_basic_login = True
auth.basic(basic_auth_realm='any realm is fine')
return service()
@service.soap('MyFunction',returns={'result':int},args={'a':int,'b':int,})
def myfunction(a, b):
return a + b
def call():
return service()
Call it with:
from gluon.contrib.pysimplesoap.client import SoapClient
client = SoapClient(wsdl="http://
..../app/mycontroller/call_w_auth/soap?WSDL")
response = client.MyFunction(a=1,b=2)
return response['result']
2013/9/4 Dave S <[email protected]>
> I'm a newbie to web2py, but the book examples have gotten me a long ways,
> and the forum (GG) has helped, also.
>
> I have set up a pretty simple SOAP service, and have turned on Basic AUTH.
> I get the correct results when the client provides the correct header, so
> all that's good. But I'd like to return HTTP 401 (Unauthorized) instead of
> HTTP 303 (See Other) if the header is missing or incorrect. What's the
> best way to do this? Should I give up the "auth.requires_login" decorator
> on my call() controller and use the procedural technique of calling
> auth.basic() in the body (sec 9.25, pg 452 of the 5th ed). Or should I use
> the catch303 technique of this earlier post?
> <https://groups.google.com/d/msg/web2py/zC6UKTM0qRY/_dE1vnkmYsMJ>
>
> Footnote: On the remote machines, I'm using 2 different clients: SUDS
> from Python, and a simple Java client based on java.xml.soap
> (SOAPConnectionFactory). In the latter, the 303 error gets turned into an
> ugly exception about Invalid Content-Type ([...].saaj.SOAPExceptionImpl.
> Is this the exception I should be catching to gracefully report the
> mess-up? And can I expect a 401 to raise the same exception?
>
> /dps
>
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