Works perfect Adi and Villas,
much appreciated.
Here's the complete code:
def view_all_suggestions_and_comments():
query = (db.IdeaComment.ideaID==db.Idea.id) &
(db.IdeaComment.partyID==db.Party.id)
grid = SQLFORM.grid(query, ,links = [dict(header='Virtual Field',
body=lambda row: A('Add a comment!',_class="btn btn-mini",
_href=URL('comment_on_a_suggestion', vars=dict(filter=row.Idea.id))))])
return dict(grid = grid)
Alex
On Saturday, September 14, 2013 6:01:33 PM UTC-7, Adi wrote:
>
> lambda row: A('Complete',
> _class='btn', _id='btn_complete',
> _onclick='return confirm("Complete
> Order %s? (%s %s)")' % (row.id,
>
> row.shipFirstName,
>
> row.shipLastName),
> _href=URL(r=request,f='complete_order'
> ,args=[row.id]),
>
>
>
>
> On Saturday, September 14, 2013 7:41:24 PM UTC-4, Alex Glaros wrote:
>>
>> it works correctly Villas, thanks.
>>
>> how could I turn "Add a comment!" text into a button. Possible syntax
>> ",_class="btn btn-mini"", but where does it go?
>>
>> thanks,
>>
>> Alex
>>
>> On Saturday, September 14, 2013 10:23:00 AM UTC-7, villas wrote:
>>>
>>> Maybe this would work using row.idea.id like this...
>>>
>>> grid = SQLFORM.grid(query,
>>> links = [dict(header='Virtual Field',
>>> body=lambda row: A('Add a comment!', _href=URL(
>>> 'comment_on_a_suggestion', vars=dict(filter=row.idea.id <http://row.id/>
>>> )))
>>> )]
>>> )
>>>
>>>
>>> You can also now include "virtual fields" in grids, but I haven't
>>> needed to try that yet.
>>>
>>>
>>>
>>> On Saturday, 14 September 2013 15:23:49 UTC+1, Alex Glaros wrote:
>>>>
>>>> thanks Villas but I receive this error: Row' object has no attribute
>>>> 'id'
>>>>
>>>> perhaps it doesn't know which of the joined "id"s to reference
>>>>
>>>> this work-around works because it let's system know which id it is:
>>>> db.Idea.id.represent = lambda id, r: A('Add a comment!',
>>>> _href=URL('comment_on_a_suggestion', vars=dict(filter=id)))
>>>>
>>>> Alex
>>>>
>>>> On Saturday, September 14, 2013 4:56:33 AM UTC-7, villas wrote:
>>>>>
>>>>> Try this...
>>>>>
>>>>> grid = SQLFORM.grid(query,
>>>>> links = [dict(header='Virtual Field',
>>>>> body=lambda row:
>>>>> A('Add a comment!', _href=URL('comment_on_a_suggestion', vars=dict(filter=
>>>>> row.id)))
>>>>> )]
>>>>> )
>>>>>
>>>>>
>>>>> On Friday, 13 September 2013 21:57:28 UTC+1, Alex Glaros wrote:
>>>>>>
>>>>>> I tried this but got "lambda requires 2 args, 1 given" error, plus
>>>>>> need to be able to pass Idea.id parm to the button. How to do that?
>>>>>>
>>>>>> grid = SQLFORM.grid(query,links = [dict(header='Virtual
>>>>>> Field',body=lambda id, r: A('Add a comment!',
>>>>>> _href=URL('comment_on_a_suggestion', vars=dict(filter=id))))])
>>>>>>
>>>>>> On Friday, September 13, 2013 1:33:35 PM UTC-7, villas wrote:
>>>>>>>
>>>>>>> Hope this helps...
>>>>>>>
>>>>>>> From the book:
>>>>>>>
>>>>>>> links is used to display new columns which can be links to other
>>>>>>> pages. The links argument must be a list of
>>>>>>> dict(header='name',body=lambda
>>>>>>> row: A(...)) where header is the header of the new column and bodyis a
>>>>>>> function that takes a row and returns a value. In the example, the
>>>>>>> value is a A(...) helper.
>>>>>>>
>>>>>>> Example:
>>>>>>>
>>>>>>> linkbtns = [
>>>>>>> lambda row: SPAN('Mag',_class="label label-success"
>>>>>>> ) \
>>>>>>> if row.status =='Y' else '',
>>>>>>> lambda row: SPAN('Web',_class="label label-success"
>>>>>>> ) \
>>>>>>> if row.is_active else '',
>>>>>>> lambda row: A( I('',_class="icon-eye-open")+' View'
>>>>>>> ,
>>>>>>> _href=URL("view",args=[row.id]),
>>>>>>> _class="btn btn-small"
>>>>>>> ),
>>>>>>> lambda row: A( I('',_class="icon-edit")+' Edit',
>>>>>>> _href=URL("edit",args=[row.id]),
>>>>>>> _class="btn btn-small"
>>>>>>> ),
>>>>>>> lambda row: A( I('',_class="icon-road")+' Map',
>>>>>>> _href=URL('default','geocoder',
>>>>>>> args=['caclient',row.id],vars={'title':row.business}),
>>>>>>> _class="btn btn-small"
>>>>>>> ),
>>>>>>> ]
>>>>>>> grid = SQLFORM.grid(....... links=linkbtns, .......)
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Friday, 13 September 2013 21:00:56 UTC+1, Alex Glaros wrote:
>>>>>>>>
>>>>>>>> How do I add a button "Add a comment!" in every row of a grid? It's
>>>>>>>> a kind of virtual column.
>>>>>>>>
>>>>>>>> The below works, it takes user exactly to the correct row in the
>>>>>>>> next table, but I use up one of the fields (Idea.id). How do I just
>>>>>>>> create
>>>>>>>> text/virtual column that doesn't sacrifice existing field?
>>>>>>>>
>>>>>>>>
>>>>>>>> def view_all_suggestions_and_comments():
>>>>>>>> db.Idea.id.represent = lambda id, r: A('Add a comment!',
>>>>>>>> _href=URL('comment_on_a_suggestion', vars=dict(filter=id)))
>>>>>>>> query = (db.IdeaComment.ideaID==db.Idea.id) &
>>>>>>>> (db.IdeaComment.partyID==db.Party.id)
>>>>>>>> grid = SQLFORM.grid(query)
>>>>>>>> return dict(grid = grid)
>>>>>>>>
>>>>>>>>
>>>>>>>> I read the book but need exact syntax for this situation.
>>>>>>>>
>>>>>>>> Thanks,
>>>>>>>>
>>>>>>>> Alex Glaros
>>>>>>>>
>>>>>>>
--
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