uhm: seems that you didn't quite get how lambda works.....
lambda row : something(row)
equals to
def something(row):
return 'a'
lambda is used just to "inline" a small snippet of code.
In your case, you need to generate the link from the field pdf_path, but
you need to take the pdf_path from the row you're passing to the
function.....
def generate_link(row):
return A('whatever', _href=URL('default', 'download',
args=row.pdf_path))
that, "transformed" to the "lambda format" is
lambda row : A('whatever', _href=URL('default', 'download',
args=row.pdf_path))
As for having the URL absolute instead of relative, use the host parameter
of the A helper.
On Thursday, October 3, 2013 5:32:20 PM UTC+2, Gael Princivalle wrote:
>
> Hi.
>
> In a table I have that:
> db.define_table('products',
> Field('code', unique=True),
> Field('description'),
> Field('brand'),
> Field('pdf_path'))
>
> I want to have a sqlform.grid that gone have all links to pdf_path field.
> These are absolute links like "http://www.example.com/mycatalogue.pdf";
>
> Here is my controller:
> def products_listing():
> links = [lambda row: A('pdf', _href=db.products.pdf_path)]
> grid = SQLFORM.grid(db.products, orderby=db.products.code,
> links=links,links_in_grid=True)
> return dict(grid=grid)
>
> I have two problems, path is relative because it begin at my website
> http://..../my_application/default
> And the products.pdf_path field is not considered like a filed, but like a
> string.
>
> The result is: http://..../my_application/default/products.pdf_path
>
> I've tried also to play with the URL helper but without result.
>
> An idea ?
>
> Thanks.
>
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