Hello, If start web2py from command line with this command :
python web2py.py -a 'asdf' -i 127.0.0.1 -p 8001 -S myapp -M auto I am expecting that "request.env.http_host" to return : 127.0.0.1:8001 But I always get 8000, is something wrong with my command? I also try : python web2py.py -a 'asdf' -i 127.0.0.1:8001 -S myapp -M auto And it's the same. I use web2py 2.4.7 and I try with 2.4.6 and it's the same. Thanks Richard -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
