At onvalidation the file is "inside" the form as cStringIO.StringO
instance. Specifically: form.vars.{{upload_fieldname}}.file.
You can get the contents like this:
contents = form.vars.{{upload_fieldname}}.file.getvalue()
It is then up to you to throw an error (or not as the case may be) with
form.errors.{{upload_fieldname}}.
There's a nice example here:
https://groups.google.com/d/msg/web2py/bu6Q-8slNII/pE3tKOAxjlYJ
On Thu, Nov 7, 2013 at 5:53 AM, weheh <[email protected]> wrote:
> I'm doing a file upload using SQLFORM and a field of type upload. I want
> to intercept the file during onvalidation and do some file manipulation
> before saving. While in the onvalidation routine I can see the original
> filename and form.vars.filename.file, which I can read.
>
> I'm wondering whether web2py has already created a file on the server by
> this point (in the onvalidation validation routine and before the
> form.process(onvalidation=myvalidation).accepted step)? If so, I'd like to
> get that file name at that time (during the validation step). Anybody know
> where I can find it?
>
> --
> Resources:
> - http://web2py.com
> - http://web2py.com/book (Documentation)
> - http://github.com/web2py/web2py (Source code)
> - https://code.google.com/p/web2py/issues/list (Report Issues)
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--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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