Heres an example
def stream():
"""
Stream an mp3 from an absolute path given as var
WARNING: This is definitely unsafe as it doesn't care what that path is
at all.
WARNING: Seriously this is just an example, don't use it.
"""
import os
if os.path.exists(request.vars.path)::
response.headers['Content-Type'] = 'audio/mpeg3'
return response.stream(open(request.vars.path, 'rb'),
chunk_size=4096)
else:
raise HTTP(404)
By the way, after looking at your code, I have to say, you really shouldn't
use regexes to parse XML, it's really not their purpose. It's quite simple
to refactor that using cElementTree or any other xml parser.
Good luck with your project!
Quarta-feira, 11 de Dezembro de 2013 0:11:46 UTC, Cliff escreveu:
>
> Hello.
>
> I am new to both python and web2py but have been playing with it a bit. I
> have made a simple program to listen to like artists from lastfm's API. I
> store my mp3s in a database: Artist/Track/File. It will go through my mp3s
> and find like songs and play them with jPlayer. I am stuck at playing the
> songs with jPlayer. It is trying to play my songs from
> /media/Music/artist/track.mp3 which is out of web2py's static dir. What
> would be the best way to allow web2py to access these files? If you had any
> examples that would be great.
>
> An example of the error: HTTP load failed with status 404. Load of media
> resource https://IP:8080/media/Music/mp3/Artist/Song.mp3 failed.
> (removed IP and artist/song since they were not important)
>
> This will only be used by me and on my local server so I am not concerned
> with the security issues of accessing files outside of static.
>
>
> Thanks!
>
> Cliff
>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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