The form is not accepted when it is first created, so you will always get
that error message. Instead, you want:
elif form.errors:
response.flash = 'There was an error..'
Anthony
On Monday, December 30, 2013 10:21:58 AM UTC-5, Avi A wrote:
>
> Hi,
> I have this on the view:
>
> <div>
> <input name="name" onkeyup="ajax('org_form_load.load', ['name'],
> 'org_form_target')" />
> </div>
> <div id = "org_form_target"></div>
>
> and something like this on the controller:
>
> def org_form_load():
> org_code = request.vars.name
> org_code_name = db(......).select(..............)
> if org_code_name:
> db.t_org_members.f_org_member.default = auth.user.id
> form =
> SQLFORM(db.t_org_members,onupdate=auth.archive,submit_button=
> 'something.......')
> if form.process().accepted:
> response.flash = 'Success!'
> else:
> response.flash = 'There was an error..'
> return dict(form = form, org_code_name = org_code_name)
> and on the org_form_load:
>
> {{=form}}
>
>
>
> (Before moving the form into the load page, everything went fine.)
> After moving the form to the load page, this is what it does:
> User fill correctly the organization code.
> The form appears as expected, (but not submitted yet)
> BUT I already get the " response.flash = 'There was an error..'".
> If I try to submit the form nothing flashes and form is not submitted
> either.
> Help please...
> Thanks.
>
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