Let's discuss on the developers
list<https://groups.google.com/forum/?fromgroups=#!topic/web2py-developers/k2D6MVfBEYo>
.
On Tuesday, January 7, 2014 9:52:16 PM UTC-5, Joe Barnhart wrote:
>
> Maybe the best answer is to change Row so that it always holds the full
> set of keys (table:field) and change the __getitem__ method to look up the
> key recursively if only one part is provided. Here is a sample method
> which implements this strategy of testing keys for dicts within dicts. Our
> case is a little simpler since we never "recurse" more than one level deep.
>
> def _finditem(obj, key):
> if key in obj: return obj[key]
> for k, v in obj.items():
> if isinstance(v,dict):
> item = _finditem(v, key)
> if item is not None:
> return item
>
>
> This has the advantage of working with existing code and preserving as
> much information as possible in the Row object. I have a feeling this
> could make the internals of web2py a good deal more consistent. Less
> testing for special cases is always good!
>
> -- Joe B.
>
> On Tuesday, January 7, 2014 3:48:39 PM UTC-8, Anthony wrote:
>>
>> Note, same problem with .sort (it modifies the Row objects in
>> self.records), so we should probably fix that as well (will be a bit more
>> complicated).
>>
>> Anthony
>>
>> On Tuesday, January 7, 2014 11:03:56 AM UTC-5, Anthony wrote:
>>>
>>> The Rows.find() method does the following:
>>>
>>> for row in self:
>>> if f(row):
>>> if a<=k: records.append(row)
>>> k += 1
>>> if k==b: break
>>>
>>> In a Rows object, there is self.records, which is a list of Row objects.
>>> Each Row object has at least one top-level key with the table name, and the
>>> record is stored in the value associated with that key:
>>>
>>> <Row {'person': {'first_name': 'Bob', 'last_name': 'Smith'}}>
>>>
>>> When .find() is called on a Rows object with compact=True, the __iter__
>>> method (called by the "for row in self" loop) returns a transformed version
>>> of each Row object, removing the top-level table key:
>>>
>>> <Row {'first_name': 'Bob', 'last_name': 'Smith'}>
>>>
>>> I believe this is an unnecessary transformation, and it is what is
>>> subsequently causing the .render() method to fail (the .render() method
>>> expects the top-level table key to be there, whether or not compact=True).
>>> I propose the following change to .find():
>>>
>>> for i, row in enumerate(self):
>>> if f(row):
>>> if a<=k: records.append(self.records[i])
>>> k += 1
>>> if k==b: break
>>>
>>> The above code appends self.records[i] instead of row, which preserves
>>> the original Row objects instead of including transformed objects. Anyone
>>> see any problems with that change?
>>>
>>> Also, is there any reason all of the Rows methods (i.e., find, exclude,
>>> __and__, __or__) should not be preserving the "compact" attribute of the
>>> original Rows object? Perhaps we should change them all to do so. (Note,
>>> this is a separate issue unrelated to the above problem with .find() and
>>> .render().)
>>>
>>> Anthony
>>>
>>> On Tuesday, January 7, 2014 10:47:28 AM UTC-5, Anthony wrote:
>>>>
>>>> .render() works fine on Rows objects with compact=True, and it also
>>>> works fine on the results of .sort(), .exclude(), &, and | operations. The
>>>> only problem is with the results of .find() operations when the original
>>>> Rows object has compact=True. The problem is that the .find() method
>>>> modifies the Row objects in self.records when compact=True, which it
>>>> probably should not due.
>>>>
>>>> Aside from this issue, perhaps the various Rows methods should preserve
>>>> the "compact" attribute -- not sure why they don't.
>>>>
>>>> Forwarding to the developers list for discussion.
>>>>
>>>> Anthony
>>>>
>>>> On Tuesday, January 7, 2014 3:10:00 AM UTC-5, Joe Barnhart wrote:
>>>>>
>>>>> I've been experimenting with the render method of the Rows class, and
>>>>> I am very impressed. But one drawback I found is that the Rows object
>>>>> must
>>>>> have its value set to "compact=False" to work properly with render(). It
>>>>> isn't a problem if the Rows object is used directly without any
>>>>> operators,
>>>>> but I discovered that many, if not most, Rows methods do not preserve the
>>>>> "compact" setting.
>>>>>
>>>>> For example. if you "sort" the Rows, it leaves compact=True. Ditto,
>>>>> if you use "extract" or "find" on the Rows object. The "&" and "|"
>>>>> operators also set the compact variable to "True". The upshot is that
>>>>> you
>>>>> can't use any of these operators on the Rows object and then use "render"
>>>>> on the resulting object.
>>>>>
>>>>> It is a simple change to add the preservation of the "compact" flag
>>>>> during any of these steps, but I'm unsure if this will break existing
>>>>> code.
>>>>> Other than coming up with a completely parallel set of methods, which
>>>>> leave compact set the way it came in, I can't think of another approach
>>>>> will be provably backwards-compatible.
>>>>>
>>>>> Here is an example:
>>>>>
>>>>>
>>>>> def __and__(self,other):
>>>>> if self.colnames!=other.colnames:
>>>>> raise Exception('Cannot & incompatible Rows objects')
>>>>> records = self.records+other.records
>>>>> return Rows(self.db,records,self.colnames)
>>>>>
>>>>>
>>>>> Becomes:
>>>>>
>>>>>
>>>>> def __and__(self,other):
>>>>> if self.colnames!=other.colnames:
>>>>> raise Exception('Cannot & incompatible Rows objects')
>>>>> records = self.records+other.records
>>>>> return Rows(self.db,records,self.colnames,compact=(self.compact
>>>>> or other.compact))
>>>>>
>>>>>
>>>>> In the case above, the flag compact will be set True if either of the
>>>>> participating Rows object is also "compact". My logic is, if you've lost
>>>>> the "table" values on either Rows object, you may as well lose them on
>>>>> the
>>>>> combined set.
>>>>>
>>>>> What do you think?
>>>>>
>>>>> -- Joe B.
>>>>>
>>>>>
>>>>>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/groups/opt_out.