Can you be more clear about what is happening? Are you saying if someone goes to the login page and enters incorrect credentials, they are being redirected to the index page? Auth shouldn't be doing that by default. Can you show your code?
On Monday, February 10, 2014 2:33:11 PM UTC-5, Thiago Nobre wrote: > > I already know auth.is_logged_in(), but unfortunately when the user enter > like visitor, he's not logged in, he just entered at the site without a > login. > > I need something like a login_onreject, because the visitor actually don't > sign up. > > =/ > > > 2014-02-10 17:22 GMT-02:00 Tim Richardson <[email protected]<javascript:> > >: > >> in your controller, you can access the global variable auth. >> >> You can ask >> auth.is_logged_in() is True if the user is logged in, for example. >> auth.user returns a Row telling you who is logged in. >> >> http://web2py.com/books/default/chapter/29/09/access-control#Authorization >> >> >> >> >> -- >> Resources: >> - http://web2py.com >> - http://web2py.com/book (Documentation) >> - http://github.com/web2py/web2py (Source code) >> - https://code.google.com/p/web2py/issues/list (Report Issues) >> --- >> You received this message because you are subscribed to a topic in the >> Google Groups "web2py-users" group. >> To unsubscribe from this topic, visit >> https://groups.google.com/d/topic/web2py/s2jOtL0niZM/unsubscribe. >> To unsubscribe from this group and all its topics, send an email to >> [email protected] <javascript:>. >> For more options, visit https://groups.google.com/groups/opt_out. >> > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
