I want to basically pass URL?name='table_name'
and create a form of the table name passed.
but when i try to do db.table_name
i understand it will give me a error
as it will search for a table with table_name 'table_name'
But I can't think of work around this problem...
The code snippet in default.py is as follows:
table_name=request.get_vars['name']
form = SQLFORM(db,str(table_name))
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