Try:
grid = SQLFORM.grid(db.table, user_signature=False)
Em sexta-feira, 6 de junho de 2014 13h10min34s UTC-3, LoveWeb2py escreveu:
>
> Hi Fabiano,
>
> I actually was already using grid= SQLFORM.grid(db.new_table). That is
> when I get the error.
>
> If I do grid='' to test it and just return the table without SQLFORM I can
> see it in the view, but when I apply SQLFORM I get the error 'Rows' object
> has no attribute '_db'.
>
> I'm guessing this is because of the way SQLFORM handles the grid? Could
> there be something in my model messing it up?
>
> On Friday, June 6, 2014 12:02:05 PM UTC-4, Fabiano Almeida wrote:
>>
>> Hi,
>>
>> You send var grid (see: return dict(grid=grid)). The first var grid is a
>> send var to your view, de second var grid is a local var of your
>> function.
>>
>> Then,
>> in controller use:
>> grid = SQLFORM.grid(db.new_table)
>> return dict(grid=grid)
>>
>> in the view use:
>> {{=grid}}
>>
>> Fabiano.
>>
>>
>> 2014-06-06 12:45 GMT-03:00 LoveWeb2py <[email protected]>:
>>
>>> SQLFORM isn't working for me with
>>>
>>>
>>> new_table = db(db.table1.id.belongs(record_ids)).select()
>>> if I do {{=new_table}} in my view I can see the records which belong to
>>> record_ids, but if I do:
>>>
>>> SQLFORM.grid(new_table)
>>> return dict(grid=grid)
>>>
>>>
>>> I get an error 'Rows' object has no attribute '_db'
>>>
>>> --
>>> Resources:
>>> - http://web2py.com
>>> - http://web2py.com/book (Documentation)
>>> - http://github.com/web2py/web2py (Source code)
>>> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>>
>>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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