When I used @service.jsonrpc instead,
It gave this error…
File "/Users/.../web2py/.../gluon/contrib/simplejsonrpc.py", line 108, in
<lambda>
return lambda *args: self.call(attr, *args)
File "/Users/.../web2py/.../gluon/contrib/simplejsonrpc.py", line 140, in call
self.error.get('data', None))
File "/Users/.../web2py/.../gluon/contrib/simplejsonrpc.py", line 37, in
__init__
value = "%s: %s\n%s" % (code, message, '\n'.join(data))
TypeError
The examples seemed simple enough and the code is very minimal, what seems
to be wrong?
On Tuesday, July 8, 2014 12:51:42 PM UTC+8, lyn2py wrote:
>
> Hello,
>
> I'm trying out the XML RPC to have 2 apps talk to each other, and this is
> what I have in my code (copy-pasted from this groups and web2py book):
>
> App 1:
> def test():
> import xmlrpclib
> xmlpxy = xmlrpclib.ServerProxy('
> http://127.0.0.1:8000/app2/default/call/xmlrpc')
> result = xmlpxy.do_action(3,7)
> return locals()
>
>
> App2:
> def call():
> return service()
>
>
> @service.xmlrpc
> def do_action(a,b):
> return a+b
>
>
> And I ran into this error… I'm puzzled what I am missing out to make this
> work??
>
> File
> "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/xmlrpclib.py",
> line 793, in close
> raise Fault(**self._stack[0])
> Fault: <Fault 1: '<type \'exceptions.Exception\'>:method "xml" is not
> supported'>
>
>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/d/optout.
