you're missing a parameter
response.stream(......., attachment=True)
and, BTW, instead of doing your own parsing, request.args(0) holds 10
automatically.
On Tuesday, July 15, 2014 10:24:20 AM UTC+2, Kuba Kozłowicz wrote:
>
>
> This is my controller's code, that handles requests on following URL:
>
> /app/invoices/download/<id>
> for instance:
>
>
> /app/invoices/download/10
> to download bundle of invoices, which ID is equal to 10
>
>
> def download():
> url_parts = request.url.split('/')
> bundle_id = url_parts[-1]
> try:
> bundle_id = int(bundle_id)
> except ValueError:
> raise HTTP(404)
> dir_with_id = os.path.join(BUNDLES_DIR, str(bundle_id))
>
> dir_content = [f for f in os.listdir(dir_with_id)
> if f.endswith('.zip')
> and os.path.isfile(os.path.join(dir_with_id, f))]
> if len(dir_content) != 1:
> raise HTTP(404)
> bundle_file = dir_content[0]
> bundle_file_path = os.path.join(dir_with_id, bundle_file)
> print bundle_file
>
> return response.stream(bundle_file_path, chunk_size=10**6, filename=
> bundle_file,)
>
>
> print bundle_file
> prints filename with file extension, for instance:
>
> bundle_xyz.zip
> , but I end up downloading a file called:
>
> <id>.zip
> , where <id> comes from the URL. This <id> is also the name of the
> directory that *bundle_xyz.zip* file is located in, for instance:
>
> /bundles/10/bundle_xyz.zip
>
> , after requesting /app/invoices/download/10 I end up downloading *10.zip*
> instead of *bundle_xyz.zip*.
>
> My question is how to prevent web2py's response.stream method from
> changing the filename?
>
>
>
>
>
>
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