I have two tables, *t_image2* and *t_image1*, and I would like to copy an
image (type: 'upload') from* t_image2* to *t_image1*.The tables are
something like the following:
db.define_table('t_image2',
...
Field('name', requires=[IS_NOT_EMPTY(), IS_NOT_IN_DB(db, 't_image2.name'
)], unique=True, notnull=True),
Field('image', 'upload', uploadseparate=True, autodelete=True,
uploadfolder=os_path_join(request.folder,'uploads/temp_images'),
requires=[IS_NOT_EMPTY(), IS_IMAGE()]),
...
)
db.define_table('t_image1',
...
Field('name', requires=[IS_NOT_EMPTY(), IS_NOT_IN_DB(db, 't_image1.name'
)], unique=True, notnull=True),
Field('image', 'upload', uploadseparate=True, autodelete=True,
uploadfolder=os_path_join(request.folder,'uploads/images'),
requires=[IS_NOT_EMPTY(), IS_IMAGE()]),
Field('thumbnail','upload',
uploadseparate=True, readable=True, writable=False, autodelete=
True,
uploadfolder=os_path_join(request.folder,'uploads/thumbnails'),
compute=lambda row: SMARTHUMB('t_image_user_submit', row.image, (
200, 150),
upload_folder = 'uploads/thumbnails', request = request)),
...)
It's possible to do this:
db.t_image1.insert(name = [some name], image = [image_from_t_image2.image])
But this merely copies the entries that are in one table to the other,
without making a copy of the file in question. It also doesn't trigger the
*t_image1* 'thumbnail' field's 'compute' function, which would create the
thumbnail file.
Is there a better way to perform this sort of file copy from one table to
another, such that the copy of the file is automatically made (and if
necessary, the new folder is created), and which triggers the creation of
the thumbnail? Or is it necessary to perform the folder creation and file
copy operation, as well as the creation of the thumbnail, manually? Thank
you.
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