In your table each row is a field but which record should this correspond
to?
given a record you can do
record = db.sounder[some_record_id]
a_field=[]
field_header=TR(TH('Characteristic'),TH('Typical'),TH('Comments'))
for f in db.sounder:
a_field.append([ f.label ,* record[f.name] *, f.comment ])
On Friday, 9 January 2015 22:18:16 UTC-6, Ben Lawrence wrote:
>
> I have a table with many different kinds of fields:
>
> db.define_table('sounder',
> Field('part_nr','string',label='Part Number'),
> Field('current_mA','double',label='Current
> mA',comment='max current at rated voltage'),
> Field('current_notes','string',label='Current Measurement
> Conditions',comment='e.g. current was measured at 12V (DC) or at 4.1kHz and
> 5 Vpp'),
> Field('spl','double',label='Sound Pressure Level dB at
> 30cm'),
> etc etc
>
> I would like to make a html table just like a datasheet. So In my
> controller:
> a_field=[]
> field_header=TR(TH('Characteristic'),TH('Typical'),TH('Comments'))
> for f in db.sounder:
> a_field.append([ f.label ,* f *, f.comment ])
>
> In my view (say)
> {{=TABLE(THEAD(field_header),
> TBODY(
> a_field[0],
> a_field[1],
> a_field[2],
> etc etc
> ),_class="table table-bordered")}}
>
> But you see, I need the middle column *(in red above)* to be the actual
> value of the field. The above does not give this.
>
> How can I get the actual value of the field from its object?
>
>
>
>
>
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