Thanks Anthony.
But if I replacing my code with your suggested code I have crashed the
table:
discounts.table appears corrupted
db.define_table('discounts',
Field('user_id', 'reference auth_user', requires = IS_IN_DB(
db, db.auth_user.id,
lambda r: '%s %s' % (r.first_name.upper(), r.last_name.
upper()))),
Field('brand', 'reference brands', requires = IS_IN_DB(db,
db.brands.id, '%(name)s'),
represent=lambda id, r: db.brands[id].name),
Field('xcent', type='double'))
Any idea?
Il giorno mercoledì 25 febbraio 2015 13:12:50 UTC+1, Anthony ha scritto:
>
> The third argument to IS_IN_DB is the label argument, which can either be
> Python string formatting (to which the Row object will be passed) or a
> function that takes a Row object. You cannot use arbitrary Python code
> inside Python string formatting. Try:
>
> IS_IN_DB(db, db.auth_user.id,
> lambda r: '%s %s' % (r.first_name.upper(), r.last_name.upper()))
>
> Anthony
>
>
> On Wednesday, February 25, 2015 at 4:19:29 AM UTC-5, Gael Princivalle
> wrote:
>>
>> Hello.
>>
>> In my db I have this discounts table:
>> db.define_table('discounts',
>> Field('user_id', 'reference auth_user'),
>> Field('brand', 'reference brands', requires = IS_IN_DB(db
>> , db.brands.id, '%(name)s'),
>> represent=lambda id, r: db.brands[id].name),
>> Field('xcent', type='double'))
>>
>> I would like to display the name and first name of the auth_user
>> uppercase.
>> Something like that:
>> Field('user_id', 'reference auth_user', requires = IS_IN_DB(db,
>> db.auth_user.id, '%(first_name.upper())s %(last_name.upper())s')),
>> But I've got this error:
>> 'Row' object has no attribute 'upper()'
>>
>> I've tried also like that, str(first_name).upper(), same error.
>>
>> Someone have a solution?
>>
>> Thanks, regards.
>>
>>
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