http://web2py.com/books/default/chapter/29/12/components-and-plugins#Components--LOAD-and-Ajax
On Monday, March 23, 2015 at 12:19:34 PM UTC-4, LoveWeb2py wrote:
>
> Wouldn't a LOAD/Ajax combo work better in this case and then just include
> it in your page?
>
> On Monday, March 23, 2015 at 8:41:18 AM UTC-4, Garry Smith wrote:
>>
>> Hi thanks for the reply.
>>
>> What I was trying to do in the original code was return the data to a div
>> not to a specified page, so what you are saying is correct.
>> The part about the table, is that it seems to only iterate over the first
>> record, maybe the code is different for tables, because it has to iterate
>> for each row and data.
>> Not sure how to solve at the moment, I'm new to web2py, I'm use to MVC in
>> Php with codeigniter, so its a bit off a learning curve, especially with
>> jquery and ajax.
>> With codeigniter I could send back, Jquery back through with html, which
>> was then embedded into the page and would just work.
>> So on to the next part of learning python and web2py.
>>
>> Thanks for your reply.
>>
>> On Sunday, 22 March 2015 20:45:18 UTC, Anthony wrote:
>>>
>>> Just to clarify the original problem, when a controller action returns a
>>> dictionary (as in your original code), web2py assumes it should then look
>>> for an execute a view. If a dedicated view does not exist for the action,
>>> it will default to generic.html (though this is disabled by default, except
>>> for local requests in the welcome app). So, you should either create a view
>>> that generates the HTML you want based on what is returned in the
>>> dictionary, or you should not return a dictionary.
>>>
>>> Instead of a dictionary, you can directly return HTML as a string (which
>>> is what your new code does) by applying the .xml() method to the UL helper.
>>> However, you don't actually need to apply the .xml() method, because if you
>>> return an HTML helper object, web2py will automatically serialize it to a
>>> string for you.
>>>
>>> As for returning an HTML table rather than a UL, there's no reason you
>>> couldn't do that instead. Just create a TABLE object and return that.
>>>
>>> Anthony
>>>
>>> On Saturday, March 21, 2015 at 8:17:06 PM UTC-4, Garry Smith wrote:
>>>>
>>>> Hi with your help I have manage to get the links working using the
>>>> following code:-
>>>>
>>>> def artist():
>>>>
>>>> rows = db().select(db.media.artist,db.media.id, groupby =
>>>> db.media.artist)
>>>>
>>>> links = map(lambda row:A(row.artist,
>>>> callback=URL('album',vars=dict(id=row.id)), target='album'), rows)
>>>>
>>>> test = UL([LI(link) for link in links]).xml()
>>>>
>>>> return test
>>>>
>>>> This now returns the links in a list.
>>>> Would off like it in a table, but it only returns first record, not
>>>> sure how I could itterate to return the table rows.
>>>>
>>>> Thanks again
>>>>
>>>> On Saturday, 21 March 2015 18:19:02 UTC, Garry Smith wrote:
>>>>>
>>>>> Hi
>>>>> I'm trying to return the some links to a div. I have made links with
>>>>> some information from the database and using the A htlm helper.
>>>>> The problem I am having is getting the data back correctly, I am
>>>>> getting the links back correctly, but I am being sent a full web page
>>>>> with
>>>>> the links, which is then put in the div.
>>>>>
>>>>> *VIEW*
>>>>> this is link which is sent to the artist page, which gets all the
>>>>> distinct artist.
>>>>>
>>>>> {{=A('click' , callback=URL('artist'), target="artist")}}
>>>>>
>>>>> *CONTROLLER*
>>>>>
>>>>> This is the controller that makes the links and returns to the div as
>>>>> specified in above link.
>>>>>
>>>>> def artist():
>>>>> rows = db().select(db.media.artist,db.media.id, groupby =
>>>>> db.media.artist)
>>>>>
>>>>> links = []
>>>>>
>>>>> for row in rows:
>>>>> a = str(row.id)
>>>>> b = 'album?id='
>>>>> c = b+a
>>>>> l = row.artist
>>>>> f = A(l , callback=URL(c), target="album")
>>>>> links.append(f)
>>>>>
>>>>> return dict(links=links)
>>>>>
>>>>> I have tried diffrent ways to solve this, but to no avail, all I want
>>>>> is to return the links to div.
>>>>>
>>>>> What i am trying to do is rewrite a media player, which I wrote in php
>>>>> a few years ago, but I am having few issues writing a returning links on
>>>>> the sly.
>>>>>
>>>>> Thanks in advance for any help.
>>>>>
>>>>>
>>>>>
--
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