Hello
What would be the best way to return server error in try, except to user
I have multiple functions and i have try, except in each and I would like
to show user in alert what the error was (only for selected functions)
my except is
except Exception as e:
script.update_record(sc_status = 10)
exc_type, exc_obj, exc_tb = sys.exc_info()
fname = os.path.split(exc_tb.tb_frame.f_code.co_filename)[1]
errmsg = [exc_type, fname, exc_tb.tb_lineno,e.__doc__ ,
e.message]
print "errmsg ", errmsg
print(exc_type, fname, exc_tb.tb_lineno)
print e.__doc__
print e.message
return dict(status = 666, errmsg = errmsg)
any suggestions
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/d/optout.