m, cm = db.meeting, db.co_meet
q = m.id == cm.ref_meeting
q = q & (cm.ref_company == 1)
grid = SQLFORM.grid(q, field_id=m.id, fields=[m.id, m.title])
On Sun, May 31, 2015 at 4:48 AM, Ben Lawrence <[email protected]> wrote:
> Both of your answers give a grid of co_meet.
>
> What would the query be in SQLFORM.grid such that it would be a grid of
> db.meeting for one company (not db.co_meet)?
>
>
> On Thursday, May 7, 2015 at 8:26:47 PM UTC-7, 黄祥 wrote:
>>
>> had you tried it?
>> another work around is u can use smartgrid constraints
>> e.g.
>> def test():
>> table = db.co_meet
>> query = db.co_meet.ref_company == 1 # whatever value that refer to
>> table company
>> grid = SQLFORM.smartgrid(table, constraints = dict(co_meet=query) )
>> return locals()
>> best regards,
>> stifan
>>
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--
Massimiliano
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