oh i forget to ask, and how can i now display on the html page, which user are online? thanks massimo for your time ;)
On 15 Jun., 20:24, pk <[email protected]> wrote: > thanks massimo ;) > > On 15 Jun., 20:07, mdipierro <[email protected]> wrote: > > > Put this in your layout.html > > > <script language="Javascript" type="text/javascript"> > > jQuery(document).ready(function(){ > > setTimeout("keepalive('{{=URL > > (r=request,c='default',f='keepalive')}}')",2000);}); > > > </script> > > > This in your model > > > db.define_table('online',SQLField('user_id',db.auth_user),SQLField > > ('last_visit','integer')) > > > This in your default.py controller > > > @auth.requires_login() > > def keepalive(): > > import time > > if not db.online[auth.user.id]: > > db.online.insert(user_id=auth.user.id,last_visit=time.time()) > > else: > > db(db.online.user_id==auth.user.id).update(last_visit=time.time > > ()) > > > and use this function to check > > > def is_user_online(user_id): > > import time > > dt = 5000 > > return db(db.online.user_id==user_id) > > (db.online.last_visit>time.time()-dt.count()>0 > > > Massimo > > > On Jun 15, 12:57 pm, pk <[email protected]> wrote: > > > > hi, > > > > is there a available command or function to check whether the user > > > (from auth.user) is online or not? > > > > thanks > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
